Q. Write a program that depending upon user's choice, either pushes or pops an element in a stack.
You can understand by Watching video :-
Answer =
stack = [ ] while True : com = input("Enter ( Push or Pop ) : ") if com == "push" or com == "Push" : num = int(input("Enter a number : ")) stack.append(num) elif len(stack) == 0 : print("Underflow") elif com == "pop" or com == "Pop" : stack.pop() yes = input ("Enter ( Yes or no ) : ") if yes == "No" or yes == "no": print("Thank you !!!!") break print(stack)
Output :-
Enter ( Push or Pop ) : push
Enter a number : 5
Enter ( Yes or no ) : yes
Enter ( Push or Pop ) : push
Enter a number : 6
Enter ( Yes or no ) : yes
Enter ( Push or Pop ) : push
Enter a number : 3
Enter ( Yes or no ) : yes
Enter ( Push or Pop ) : pop
Enter ( Yes or no ) : yes
Enter ( Push or Pop ) : push
Enter a number : 1
Enter ( Yes or no ) : no
Thank you !!!!
[5, 6, 1]
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Do program will run without else part????
ReplyDeleteYes, you can run this program in your pc.
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