Q. Write a program that depending upon user's choice, either pushes or pops an element in a stack.
You can understand by Watching video :-
    
  Answer = 
stack = [ ]
while True :
    com = input("Enter ( Push or  Pop ) : ")
    
    if com == "push" or com == "Push" :
        num = int(input("Enter a number : "))
        stack.append(num)
    elif  len(stack) == 0 :
        print("Underflow")
        
    elif com == "pop" or com == "Pop" :
        stack.pop()
    yes = input ("Enter ( Yes or no ) : ")
    if yes == "No" or yes == "no":
        print("Thank you !!!!")
        break
    print(stack)
Output :-
Enter ( Push or  Pop ) : push
Enter a number : 5
Enter ( Yes or no ) : yes
Enter ( Push or  Pop ) : push
Enter a number : 6
Enter ( Yes or no ) : yes
Enter ( Push or  Pop ) : push
Enter a number : 3
Enter ( Yes or no ) : yes
Enter ( Push or  Pop ) : pop
Enter ( Yes or no ) : yes
Enter ( Push or  Pop ) : push
Enter a number : 1
Enter ( Yes or no ) : no
Thank you !!!!
[5, 6, 1]
>>> 
Do program will run without else part????
ReplyDeleteYes, you can run this program in your pc.
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