Conditional and Iterative Statements || Sumita Arora || Class 11 || Practical || Computer Science || Solution


P.I.P: - 4.1











 


 
	  

 

 
	 (a) 
	 The user enters:0 for x; 1 for y, and 1 for z 
	  

 

 
	 (b) 
	 The user enters:-1 for x 50 for y, and 100 for z 
	  

 

 
	 (c) 
	 The user enters:10 for x; 50 for y, and 15 for z 
	  

 

 
	 (d) 
	 The user enters:-1 for x; -50 for y, and -100 for z 
	  

 








 
	  
	 For k's this value 
	 Output 
	 Flow-of-execution 

 

 
	 (i) 
	 79 
	  
	  

 

 
	 (ii) 
	 29 
	  
	  

 

 
	 (iii) 
	 39 
	  
	  

 

 
	 (iv) 
	 59 
	  
	  

 

 
	 (v) 
	 30 
	  
	  

 

 
	 (vi) 
	 50 
	  
	  

 

 
	 (vii) 
	 60 
	  
	  

 







 
	 S. No. 
	 Input values 
	 Output produced 

 

 
	 (a) 
	 x = 2 and y = 5? 
	  

 

 
	 (b) 
	 x = 3 and y = 1? 
	  

 

 
	 (c) 
	 x = 1 and y = 1? 
	  

 

 
	 (d) 
	 x = 4 and y = 3? 
	  

 

























 
	  
	 Code 
	 Output 

 

 
	 (a) 
	 if not 3:
    print ("Tricky \n")
print ("Yes")		 
	 
 

 

 
	 (b) 
	 if 3:
    print ("Tricky again")
else:
    print ("Am I right?")
    print ("No???")		 
	 
 

 

 
	 (c) 
	 if (0):
    print ("Third time Tricky")
    print ("Am I right?")		 
	 
 

 

 
	 (d) 
	 if (not 0):
    print ("Fourth time again \n")
    print ("No??")		 
	 
 

 

 
	 (e) 
	 if 0:
    print ("Plz! Not again \n")
else:
    print ("Promise, it's the last time")
print ("Thank God!!")		 
	 
 

 












 
	 Grade 
	 Remarks 
	 Marks 

 

 
	 A 
	 (Level 4, above agency-normalized standards) 
	 80% and above 

 

 
	 B 
	 (Level 3, at agency-normalized standards) 
	 70-79% 

 

 
	 C 
	 (Level 2, below, but approaching agency-normalized standards) 
	 60-69% 

 

 
	 D 
	 (Level 1, well below agency-normalized standards) 
	 50-59% 

 

 
	 E 
	 (Level 1-, too below agency-normalized standards) 
	 40-49%


P.I.P: - 4.2





 
	  
	 Program Code 
	 Dry run (determine output on paper) 
	 Actual output (run code and find out) 

 

 
	 (a) 
	 for a in 10, 12, 14, 16, 18:
    print (a)		 
	  
	  

 

 
	 (b) 
	 for i in range (5):
    print (i)		 
	  
	  

 

 
	 (c) 
	 for i in range (0,5):
    print (j)		 
	  
	  

 

 
	 (d) 
	 for k in range (3,0):
    print (k)		 
	  
	  

 

 
	 (e) 
	 for c in "Apple":
    print (c)		 
	  
	  

 





 
	  
	 Program Code 
	 Dry run (determine output on paper) 
	 Actual output code and find (run out) 

 

 
	 (a) 
	 a = 8
while (a > 0):
    print ("Gotcha!")
    a = a - 3
else:
    print ("Going out!")		 
	 
 
	 
 

 

 
	 (b) 
	 a = 8
while (a > 0):
    print ("Gotcha!")
else:
    print ("Going out!")		 
	 
 
	 
 

 

 
	 (c) 
	 a = 8
while (a > 0):
    print ("Gotcha!") 
    a = a + 3
else:
    print ("Going out!")		 
	 
 
	 
 

 

 
	 (d) 
	 a = 8
while (a > 0):
    print ("Gotcha!")
    a = a - 3
    ifa ==5:
        break
else:
    print ("Going out!")		 
	 
 
	 
 

 





 
	 i = 0
while i < 10:
    i +=1
    if i % 2 == 0:
        print(i)		 
	  

 

 
	 i = 0
while i > 10:
    i +=1
    if i % 2 == 0:
        print(i)		 
	  

 

 
	 i = 0
while i < 1:
    i -= 1
    if i % 2 == 0:
        print(i)		 

 



















 
	 Given 
	 Correct Code 

 

 
	 for iMus range (10)
b = 19 + iMus
    print (b)		 
	  

 

 
	 while k < 10 :
print (k)
k = k + 2		 

 

 
	 a = 5
while a < 10:<10: 1="" 2="" a="" deg="" else="" print="" td="">		 

 

 
	 a = 5
while a
    print (a)
    a -=1		 
	  

 

 
	 For p in range (3)
    for q in range (3)
        print (p * q)
    else:
    print ("outer loop ends")		 
	  

 

 
	 for p in range(3)
    for q in range(3)
        print ( p * q)
    elif:
    print ("loop ends")
else:
    print ("loop over")		 
	  

 






 
	 (a) 
	 j = 0
while (j < 50):
    print ("Hello World")		 
	  

 

 
	 (b) 
	 j = 25
while (25 <= j <= 30):
    print ("Temp variable = ", j)
    j = j + 1		 
	  

 

 
	 (c) 
	 j = 25
while (25 <= j < 30):
    print ("Temp variable =", j)
    j = j + 1		 
	  

 

 
	 (d) 
	 # Assume Boolean variable b is not known
b = True
sum = 0
while b:
    sum = sum + 5
    print (sum)
    if (b or not b):
        break		 
	  

 

 
	 (e) 
	 a = 1.0
for i in range (1,4):
    a = a * 3
print (a)
print (j)		 
	  

 

 
	 (f) 
	 a = 1.0
for j in range (4):
    a = a * j
print (a)
print (j)		 
	  

 

 
	 (g) 
	 for j in 'abcde':
    print (j, end = '')
    if j > 'c':
        break


































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