Q .What is the output of following code fragments?
(i)
def increment(n):
n. append([4])
return n
L = [1, 2, 3]
M = increment(L)
print(L, M)
(ii)
def increment(n):
n. append([49])
return n[0], n[1], n[2], n[3]
L = [23, 35, 47]
mi, m2, m3, m4 = increment (L)
print(L)
print(mi, m2, m3, m4)
print(L[3] == m4)
Answer =
(i)
Output:-
[1, 2, 3, [4]] [1, 2, 3, [4]]
(ii)
Output: -
[23, 35, 47, [49]]
23 35 47 [49]
True
please explain for i)
ReplyDeleteThe increment function takes a list n as input.
DeleteInside the function, the .append([4]) method adds a new element, a list containing the value 4, to the end of the list n. Since n refers to the same list object as the one originally assigned to L, this modification is reflected in L as well.
The function returns the modified list, which is still L.
The line print(L, M) prints the values of L and M. Because M is assigned the result of increment(L), which ultimately points to the same modified list object, both L and M will contain [1, 2, 3, [4]].
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