Q. Consider the following string myAddress:


myAddress = "WZ-1,New Ganga Nagar,New Delhi"


What will be the output of following string operations :


i. print(myAddress.lower())

ii. print(myAddress.upper())

iii. print(myAddress.count('New'))

iv. print(myAddress.find('New'))

v. print(myAddress.rfind('New'))

vi. print(myAddress.split(','))

vii. print(myAddress.split(' '))

viii. print(myAddress.replace('New','Old'))

ix. print(myAddress.partition(','))

x. print(myAddress.index('Agra'))


Answer:-

i =  wz-1,new ganga nagar,new delhi
ii =  WZ-1,NEW GANGA NAGAR,NEW DELHI
iii =  2
iv =  5
v =  21
vi =  ['WZ-1', 'New Ganga Nagar', 'New Delhi']
vii =  ['WZ-1,New', 'Ganga', 'Nagar,New', 'Delhi']
viii =  WZ-1,Old Ganga Nagar,Old Delhi
xi =  ('WZ-1', ',', 'New Ganga Nagar,New Delhi')
x = error because Agra is not present in myAddress


Post a Comment

You can help us by Clicking on ads. ^_^
Please do not send spam comment : )

Previous Post Next Post