Write a function that receives an octal number and prints the equivalent number in other number bases

Q. Write a function that receives an octal number and prints the equivalent number in other number bases i.e., in decimal, binary and hexadecimal equivalents.

Answer :-

def oct2others (n) :
    print("Passed octal number : ", n)
    numString = str(n)
    decNum = int(numString, 8)
    print("Number in Decimal: ", decNum)
    print("Number in Binary:", bin(decNum))
    print("Number in Hexadecimal : ", hex(decNum))

num = int(input ("Enter an octal number :"))
oct2others (num)

Please recall that bin() and hex( ) do not return numbers but return the string-representations of equivalent numbers in binary and hexadecimal number systems respectively.

Output :-

Enter an octal number :12345
Passed octal number :  12345
Number in Decimal:  5349
Number in Binary: 0b1010011100101
Number in Hexadecimal :  0x14e5
>>>